\[O(g)+{{e}^{-}}\xrightarrow{{}}{{O}^{-}}(g);{{\Delta }_{f}}{{H}^{O-}}=-141\,kJ\,mo{{l}^{-}}\] |
\[{{O}^{-}}(g)+{{e}^{-}}\xrightarrow{{}}{{O}^{2-}}(g);{{\Delta }_{f}}{{H}^{O-}}=+780\,kJ\,mo{{l}^{-}}\] |
Thus the process of formation of \[{{O}^{2-}}\]in gas phase is neon. It is due to the fact that |
A) Oxygen is more electronegative
B) Addition of electron in oxygen results in larger size of the ion
C) Electron repulsion outweighs the stability gained by achieving noble gas configuration
D) \[{{O}^{-}}\]ion has comparatively smaller size than oxygen atom
Correct Answer: C
Solution :
Second electron gain enthalpy is positive (energy absorbed) due to more repulsion experienced by incoming electrons while entering uninegative anion.You need to login to perform this action.
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