A) 96500C
B) \[2\times 96500\,C\]
C) 9650 C
D) 96.50 C
Correct Answer: C
Solution :
\[MnO_{4}^{2-}\xrightarrow{{}}MnO_{4}^{-}+{{e}^{-}}\] 0.1 mol\[MnO_{4}^{2-}\] will loose 0.1 mol electrons. The quantity of electricity required to oxidise \[MnO_{4}^{-}\] completely will be 0.1 faraday, i.e., 9650 C.You need to login to perform this action.
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