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NEET Sample Paper NEET Sample Test Paper-24

  • question_answer
    When \[\,0.1\,mol\,MnO_{4}^{2-}\]is oxidised the quantity of electricity required to completely oxidise\[MnO_{4}^{2-}\]to\[MnO_{4}^{-}\]is

    A)  96500C                       

    B) \[2\times 96500\,C\]

    C)  9650 C                        

    D)  96.50 C

    Correct Answer: C

    Solution :

    \[MnO_{4}^{2-}\xrightarrow{{}}MnO_{4}^{-}+{{e}^{-}}\] 0.1 mol\[MnO_{4}^{2-}\] will loose 0.1 mol electrons. The quantity of electricity required to oxidise \[MnO_{4}^{-}\] completely will be 0.1 faraday, i.e., 9650 C.


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