A) \[7/6m\]
B) \[5/6m\]
C) \[29/6m\]
D) \[3m\]
Correct Answer: A
Solution :
By work-energy theorem, \[Wmg+{{W}_{function}}\] \[={{K}_{f}}-{{K}_{f}}-mgh-\mu \,mgd=0-\frac{1}{2}m\upsilon _{0}^{9}\] \[\Rightarrow \]\[-10\times 1.1-0.6\times 10\times d=\frac{1}{2}\times {{6}^{2}}-(11+6d)\] \[\Rightarrow \] \[11+6d=18,\] \[d=\frac{7}{6}m.\]You need to login to perform this action.
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