A) Propadiene
B) Propylene
C) Allyl alcohol
D) Acetyl chloride
Correct Answer: A
Solution :
\[\underset{Allyl\,\,Chloride}{\mathop{\underset{Cl}{\mathop{\underset{|}{\mathop{C}}\,}}\,{{H}_{2}}}}\,-CH=C{{H}_{2}}\xrightarrow[-HCl]{KOH\,\,(alco.),\Delta }\underset{\text{Propadiene}}{\mathop{\text{C}{{\text{H}}_{\text{2}}}\text{=C=C}{{\text{H}}_{\text{2}}}}}\,\]
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