A) \[[M{{L}^{2}}{{T}^{-2}}{{A}^{-1}}]\]
B) \[[M{{L}^{0}}{{T}^{-2}}{{A}^{-2}}]\]
C) \[[{{M}^{o}}{{L}^{-2}}{{T}^{-2}}{{A}^{-2}}]\]
D) \[[ML{{T}^{-1}}{{A}^{3}}]\]
Correct Answer: A
Solution :
Electric flux \[\varepsilon =\frac{d\phi }{dt}\] \[\Rightarrow \] \[[\phi ]=[\varepsilon ]\,\,[t]\] \[\left[ \frac{M{{L}^{2}}{{T}^{-2}}}{AT} \right][T]=[M{{L}^{2}}{{T}^{-2}}{{A}^{-1}}]\] Magnetic flux and electric flux having saming dimension.
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