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NEET Sample Paper NEET Sample Test Paper-27

  • question_answer
    The number of turn in primary and secondary turns of a transformer are 1000 and 3000 respectively. If 80V AC is supplied to the primary coil of the transformer, the potential difference per turn of the secondary coil would be:

    A)  \[200\,V\]                   

    B)  \[2400\,V\]

    C)  \[0.24\,V\]                  

    D)  \[0.08\,V\]

    Correct Answer: D

    Solution :

    From the formula, \[\frac{es}{ep}=\frac{{{N}_{s}}}{{{N}_{p}}}\] Here :    \[{{N}_{s}}=3000,\,\,{{N}_{p}}=1000\] and              \[ep=80\]volt             \[\frac{es}{ep}=\frac{{{N}_{s}}}{{{N}_{p}}}=\frac{3000}{1000}=3\]             \[\Rightarrow \]            \[\frac{es}{80}=3\]                         \[es=80\times 3=240\] 89Volt \[\therefore \] Potential difference across one turn is given by             \[\frac{es}{{{N}_{s}}}=\frac{240}{3000}V/turn=0.08V/turn\]


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