A) \[{{H}_{2}}S>Si{{H}_{4}}<N{{H}_{3}}<B{{F}_{3}}\]
B) \[N{{H}_{3}}<{{H}_{2}}S<Si{{H}_{4}}<B{{F}_{3}}\]
C) \[{{H}_{2}}S<N{{H}_{3}}<Si{{H}_{4}}<B{{F}_{3}}\]
D) \[{{H}_{2}}S<N{{H}_{3}}<B{{F}_{3}}<Si{{H}_{4}}\]
Correct Answer: C
Solution :
The correct order of bond angle is as:| \[{{H}_{2}}S\] < | \[N{{H}_{3}}\] < | \[Si{{H}_{4}}\] < | \[B{{F}_{3}}\] |
| \[{{92.6}^{o}}\] | \[{{107}^{o}}\] | \[{{109}^{o}}28'\] | \[{{120}^{o}}\] |
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