A) \[N{{F}_{3}}\]
B) \[NC{{l}_{3}}\]
C) \[N{{I}_{3}}\]
D) \[NB{{r}_{3}}\]
Correct Answer: C
Solution :
Since the electronegativity of X in \[\overset{\bullet \bullet }{\mathop{N}}\,{{X}_{3}}\] decreases from F to I hence, the tendency of N to donate its lone pair of electrons increases and therefore \[N{{I}_{3}}\] is the most basic trihalide of nitrogen.
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