question_answer

The e.m.f. of a Daniell cell at \[298\text{ }K\] is \[{{E}_{1}}\]. \[Zn/ZnS{{O}_{4}}\,\,(0.01M||CuS{{O}_{4}}\,(1.0M)/Cu\] When the concentration of \[ZnS{{O}_{4}}\] is \[1.0\text{ }M\] and that of \[CuS{{O}_{4}}\] is \[0.01\text{ }M,\] the e.m.f. is changed to \[{{E}_{2}}\]. What is the relationship between \[{{E}_{1}}\] and \[{{E}_{2}}\] :-

A)  \[{{E}_{1}}>{{E}_{2}}\]          

B)  \[{{E}_{1}}<{{E}_{2}}\]

C)  \[{{E}_{1}}={{E}_{2}}\]              

D)  \[{{E}_{2}}=0\ne {{E}_{1}}\]