A) \[\frac{9}{7}\]
B) \[\frac{7}{9}\]
C) \[\frac{49}{81}\]
D) \[\frac{81}{49}\]
Correct Answer: C
Solution :
According to question, \[\frac{{{t}_{0}}}{9}=2\pi \sqrt{\frac{4}{g}}\] and \[\frac{{{t}_{0}}}{7}=2\pi \sqrt{\frac{{{l}_{2}}}{g}}\] \[\frac{4}{{{l}_{2}}}={{\left( \frac{7}{9} \right)}^{2}}=\left( \frac{49}{81} \right)\].
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