A) Heating \[N{{H}_{4}}N{{O}_{2}}\]
B) Heating \[N{{H}_{4}}N{{O}_{3}}\]
C) \[M{{g}_{3}}{{N}_{2}}+{{H}_{2}}O\]
D) \[Na\] (comp.) \[+{{H}_{2}}{{O}_{2}}\]
Correct Answer: A
Solution :
Ammonium dichromate on heating gives \[{{N}_{2}}\]gas which is also given by heating of \[N{{H}_{4}}N{{O}_{2}}\]. \[{{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}\xrightarrow{\Delta }C{{r}_{2}}{{O}_{3}}+4{{H}_{2}}O+{{N}_{2}}\uparrow \] \[N{{H}_{4}}N{{O}_{2}}\xrightarrow{\Delta }2{{H}_{2}}O+{{N}_{2}}\uparrow \]
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