| I. \[C{{H}_{3}}NC\xrightarrow{{{H}_{3}}{{O}^{+}}}\] |
| II. \[CHC{{l}_{3}}\xrightarrow{NaOH/{{H}_{3}}{{O}^{+}}}\] |
| III. \[CC{{l}_{4}}\xrightarrow{{{H}_{3}}{{O}^{+}}}\] |
A) I, II, III
B) II, III
C) I, II
D) I, III
Correct Answer: C
Solution :
\[C{{H}_{3}}NC\xrightarrow{{{H}_{3}}{{O}^{-}}}C{{H}_{3}}N{{H}_{2}}+HCOOH\] \[CHC{{l}_{3}}\xrightarrow{NaOH}H-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,ONA\xrightarrow{{{H}_{3}}{{O}^{+}}}HCOOH\] \[CC{{l}_{4}}\xrightarrow{{{H}_{3}}{{O}^{+}}}\] no hydrolysis
You need to login to perform this action.
You will be redirected in
3 sec
