A) \[C{{u}_{2}}{{I}_{2}}\] is formed
B) \[N{{a}_{2}}S{{O}_{3}}\] is oxidized
C) \[Cu{{I}_{2}}\] is formed
D) Evolved \[{{I}_{2}}\] is reduced
Correct Answer: B
Solution :
\[CuS{{O}_{4}}+2KI\xrightarrow{{}}\underset{unstable}{\mathop{Cu{{I}_{2}}}}\,+{{K}_{2}}S{{O}_{4}}\] \[2Cu{{I}_{2}}\xrightarrow{{}}C{{u}_{2}}{{I}_{2}}+{{I}_{2}}\] \[2N{{a}_{2}}{{S}_{2}}{{O}_{3}}+{{I}_{2}}\xrightarrow{{}}2NaI+N{{a}_{2}}{{S}_{4}}{{O}_{6}}\]
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