A) \[2sec\]
B) \[4sec\]
C) \[1sec\]
D) \[6sec\]
Correct Answer: B
Solution :
If a cone filled with water is revolved in a vertical circle, then the velocity at the highest point is given by \[V\ge \sqrt{gr}\] But \[V=r\omega =r\frac{2\pi }{T}\] \[\left( \because \,\,\omega =\frac{2\pi }{T} \right)\] So, equality equation (i) becomes \[\frac{2r\pi }{T}\ge \sqrt{rg}\] \[\Rightarrow \] \[T\le \frac{2r\pi }{\sqrt{rg}}=2\pi \sqrt{\frac{r}{g}}\] \[\Rightarrow \] \[T\le 2\pi \sqrt{\frac{4}{9.8}}\] \[\Rightarrow \] \[T\le 2\times 3.14\times 0.638\] \[\Rightarrow \] \[T\le 4.0\,\,\sec \] \[\Rightarrow \] \[{{T}_{\max }}=4\sec \]
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