A) Cell is \[<\varepsilon \]
B) Cell is \[\varepsilon \]
C) Capacitor is \[>\varepsilon \]
D) Capacitor is \[<\varepsilon \]
Correct Answer: B
Solution :
If capacitor is fully charged, it draw \[{{n}_{0}}\] current when no current flows in the circuit, potential difference across the cell = emf of the cell. Potential difference across the capacitor \[\left[ \therefore \,\,V=E-ir\,as\,i=0\,\therefore \,V=E \right]\]You need to login to perform this action.
You will be redirected in
3 sec