I. \[n=4,\,l=1\] |
II. \[n=4,\,l=0\] |
III. \[n=3,\,l=2\] |
IV. \[n=2,\,l=1\] |
A) IV < II < III < I
B) II < IV < I < III
C) I < III < II < IV
D) III < I < IV < II
Correct Answer: A
Solution :
For \[~n=4,l=1;\text{ }4p\] For \[n=4,1=0;\text{ }4s\] For \[n=3,1=2;\text{ 3}d\] For \[n=2,1=1;\text{ }2p\] The order of increasing energy is as: \[2p<4s<3d<4p\] i.e. \[IV<II<III<I\]You need to login to perform this action.
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