A) In \[N_{2}^{+},\] the \[N-N\] bond weakens
B) In \[O_{2}^{+},\] \[O-O\] bond order increases
C) In \[O_{2}^{+},\] paramagnetism decreases
D) \[N_{2}^{+},\] becomes diamagnetic
Correct Answer: D
Solution :
\[{{N}_{2}}:KK{{(\sigma 2S)}^{{}}}{{(\sigma *2S)}^{2}}{{(\pi 2{{P}_{x}})}^{2}}{{(\pi 2{{P}_{y}})}^{2}}{{(\sigma 2{{P}_{z}})}^{2}}\]Bond order. \[=\frac{{{N}_{b}}-{{N}_{a}}}{2}=\frac{8-2}{2}=3\] It is diamagnetic in nature. \[N_{2}^{+}:KK{{(\sigma 2S)}^{2}}{{(\sigma *2S)}^{2}}{{(\pi 2{{P}_{x}})}^{2}}{{(\pi 2{{P}_{y}})}^{2}}{{(\sigma 2{{P}_{z}})}^{1}}\]Bond order \[=\frac{7-2}{2}=2.5\] It is paramagnetic in nature.
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