A) \[64\,{{\pi }^{2}}m/{{s}^{2}}\]
B) \[80\,{{\pi }^{2}}m/{{s}^{2}}\]
C) \[124\,{{\pi }^{2}}m/{{s}^{2}}\]
D) \[144\,{{\pi }^{2}}m/{{s}^{2}}\]
Correct Answer: D
Solution :
Maximum acceleration of particles is given by \[\alpha =a{{\omega }^{2}}=a{{(2\pi f)}^{2}}=4a{{\pi }^{2}}{{f}^{2}}\] Here, \[a=0.01m:f=60Hz\] \[\therefore \] \[\alpha =4\times 0.01\times {{\pi }^{2}}\times {{(6)}^{2}}\] \[\Rightarrow \] s\[\alpha =144{{\pi }^{2}}m/{{s}^{2}}\]
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