A) \[55.5\times {{10}^{-18}}\]
B) \[5.55\times {{10}^{-18}}\]
C) \[3.25\times {{10}^{-18}}\]
D) \[1\times {{10}^{-18}}\]
Correct Answer: C
Solution :
\[{{H}_{2}}O+{{H}_{2}}O{{H}_{3}}{{O}^{+}}+O{{H}^{-}}\] \[K=\frac{[{{H}_{3}}{{O}^{+}}][O{{H}^{-}}]}{{{[{{H}_{2}}O]}^{2}}}=\frac{{{10}^{-7}}\times {{10}^{-7}}}{{{(55.5)}^{2}}}\]
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