A) \[\text{1 }F\]
B) \[2\text{ }F\]
C) \[20\text{ }F\]
D) \[0.1\text{ }F\]
Correct Answer: A
Solution :
\[C{{a}^{2+}}+\underset{2F}{\mathop{2{{e}^{-}}}}\,\xrightarrow{{}}\underset{1\,mol\,\,=\,\,40g\,\,Ca}{\mathop{Ca}}\,\] \[\therefore \] to produce \[20\,g\,\,Ca\to 1F\] is required
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