A) \[0.06\text{ }m\]
B) \[0.3\text{ }m\]
C) \[0.01\text{ }m\]
D) \[1.0\text{ }m\]
Correct Answer: B
Solution :
\[v=\omega \sqrt{{{a}^{2}}-{{x}^{2}}}\] \[\Rightarrow \] \[x=\sqrt{{{a}^{2}}-\frac{{{v}^{2}}}{{{\omega }^{2}}}}\,(\because \,\,{{\omega }^{2}}=\frac{k}{m})\] \[x=\sqrt{{{a}^{2}}-\frac{{{v}^{2}}m}{k}}\] \[=\sqrt{{{(0.5)}^{3}}-\frac{{{(0.4)}^{2}}\times (10)}{(10)}}\] \[=\sqrt{0.25-0.16}\] \[=\sqrt{0.09}=0.3m\]
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