A) I is doubled
B) B is halved
C) r is doubled
D) both B and I are doubled
Correct Answer: D
Solution :
If a circular flexible loop is placed in a magnetic field, a deflecting torque \[(\tau )\] acts on it, this is given by, \[\tau =MB\,\sin \theta .\] Where M is dipole moment, B is magnetic field, \[\theta \]is angle between magnetic field and of loop. Also, M = IA where I is current and A the area \[(A=\pi {{r}^{2}})\] \[\pi =I\pi {{r}^{2}}B\,\sin \theta \] When B and I are doubled, the torque is doubled, so, tension is doubled.
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