A) \[\lambda =\frac{\sqrt{2meV}}{\sqrt{h}}\]
B) \[\lambda =\frac{h}{\sqrt{2meV}}\]
C) \[\lambda =\frac{\sqrt{2meV}}{h}\]
D) none of these
Correct Answer: B
Solution :
\[\because \] \[\lambda =\frac{h}{mV}\] If an electron of charge \[{{e}^{-}}\] be accelerated by a potential V then K.E.=Ve Kinetic energy is also written as \[\frac{1}{2}mVh2\] hence \[\frac{1}{2}m{{V}^{2}}=Ve\] \[V=\sqrt{\frac{2Ve}{m}}\] \[\lambda =\frac{h}{m\sqrt{\frac{2Ve}{m}}}=\frac{h}{\sqrt{2meV}}\]
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