A) \[3.0\]BM
B) \[4.9\]BM
C) \[8.9\]BM
D) \[5.9\]BM
Correct Answer: D
Solution :
The magnetic moment \[(\mu )=\sqrt{n(n+2)}\] where n = Number of unpaired electron. The atomic number of \[Mn\] is 25 \[{{M}_{n}}^{2+}:\,[Ar]3{{d}^{5}}\,{{45}^{o}}\] Number of unpaired electron = 5 \[\mu =\sqrt{5(5+2)}\] \[=\sqrt{35}\] \[=5.9BM\]
You need to login to perform this action.
You will be redirected in
3 sec
