A) \[\frac{9}{10}\]
B) \[\frac{11}{10}\]
C) \[\frac{10}{17}\]
D) \[\frac{10}{9}\]
Correct Answer: D
Solution :
According to Doppler effect in sound we have \[f={{f}_{0}}\left[ \frac{{{V}_{sound}}-{{V}_{observer}}}{{{V}_{sound}}-{{V}_{source}}} \right]\] Here, \[{{V}_{observer}}=0,\] because observer is stationary Given that: Let \[{{V}_{sound}}=V,\] \[{{V}_{source}}=\frac{V}{10}\] \[\therefore \] \[f'={{f}_{0}}\left[ \frac{V}{V-\frac{V}{10}} \right]={{f}_{0}}\left[ \frac{1}{9/10} \right]=\frac{10}{9}{{f}_{0}}\] \[\therefore \] \[\frac{f'}{{{f}_{0}}}=\frac{10}{9}\]
You need to login to perform this action.
You will be redirected in
3 sec
