NEET Sample Paper NEET Sample Test Paper-35

  • question_answer
    If \[\lambda ={{10}^{-19}}m\] changes to \[\lambda '=0.5\times {{10}^{-10}}m.\]. Find energy difference \[(\Delta E)\] give to the particle:

    A)  \[\Delta E\]is equal to \[{{\left( \frac{1}{4} \right)}^{th}}\]   of initial energy.

    B)  \[\Delta E\]is equal to \[{{\left( \frac{1}{2} \right)}^{th}}\]  of initial energy.

    C)  \[\Delta E\]is equal to twice of initial energy.

    D)  \[\Delta E\]  is equal to initial energy.

    Correct Answer: D

    Solution :

    From relation,   \[{{E}_{1}}=\frac{hc}{\lambda }\]               .....(i) and,             \[{{E}_{2}}=\frac{hc}{{{\lambda }_{2}}}\]              ......(ii) Here,            \[{{\lambda }_{2}}=\frac{{{\lambda }_{1}}}{2}\] \[\Rightarrow \] \[{{E}_{2}}-{{E}_{1}}=\frac{hc}{{{\lambda }_{2}}}-\frac{hc}{{{\lambda }_{1}}}\] \[\Rightarrow \] \[\Delta E=\frac{2hc}{{{\lambda }_{1}}}-\frac{hc}{{{\lambda }_{1}}}=\frac{hc}{{{\lambda }_{1}}}\]


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