A) \[0.064%\]
B) \[6.4\]
C) \[64%\]
D) \[6.4%\]
Correct Answer: D
Solution :
From formula, efficiency of an engine is given by, \[\eta =\left[ 1-\frac{{{T}_{2}}}{{{T}_{1}}} \right]\times 100\] Here, \[{{T}_{1}}-{{400}^{o}}C,\,{{T}_{2}}={{20}^{o}}C\] \[\Rightarrow \] \[\eta =\left( 1-\frac{273+20}{273+40} \right)\times 40\] \[\Rightarrow \] \[\eta =\left( 1-\frac{292}{131} \right)\times 100\] \[\Rightarrow \] \[\eta =0.64\times 100=6.4%\]
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