A) \[60\,m{{s}^{-1}}\]
B) \[10\,m{{s}^{-1}}\]
C) \[40\,m{{s}^{-1}}\]
D) \[20\,m{{s}^{-1}}\]
Correct Answer: D
Solution :
As the ball is thrown upward and it reaches back. Therefore, time to reach maximum height is half of total time i.e. Given speed at maximum height is zero. \[0=u-g{{t}_{\max }}\] \[\Rightarrow \] \[u=g{{t}_{\max }}\] \[(\because \,\,g=10m{{s}^{-2}})\] \[\Rightarrow \] \[u=10\times 2=20m{{s}^{-1}}\]You need to login to perform this action.
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