A) \[{{10}^{-10}}m\]
B) \[{{10}^{-20}}m\]
C) \[{{10}^{-30}}m\]
D) \[{{10}^{-40}}m\]
Correct Answer: C
Solution :
\[\lambda =\frac{h}{m\upsilon }\] \[=\frac{6.625\times {{10}^{-34}}\times 60\times 60}{0.2\times 5}=2.3\times {{10}^{-30}}m\]
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