A) \[N{{O}_{2}}\]
B) \[NO_{2}^{-}\]
C) \[NO_{2}^{+}\]
D) \[NO_{3}^{-}\]
Correct Answer: C
Solution :
In aromatic nitration \[NO_{2}^{+}\] (nitronium ion) acts as an electrophile. \[HN{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}\underset{electrophile}{\mathop{NO_{2}^{+}}}\,+HSO_{4}^{-}+{{H}_{2}}O\]
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