NEET Sample Paper NEET Sample Test Paper-36

  • question_answer From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m/s. The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is (Take\[g=10\text{ }m/{{s}^{2}}\])

    A)  5:7         

    B)  7:5

    C)  3:6         

    D)  6:3

    Correct Answer: B

    Solution :

     \[{{S}_{3rd}}=10+\frac{10}{2}(2\times 3-1)=35\,m\] \[{{S}_{2nd}}=10+\frac{10}{2}(2\times 2-1)=25\,m\Rightarrow \frac{{{S}_{3rd}}}{{{S}_{2nd}}}=\frac{7}{5}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner