A) 20 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
B) 20 litres ammonia, 20 litres nitrogen, 20 litres hydrogen
C) 10 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
D) 20 litres ammonia, 10 litres nitrogen, 30 litres hydrogen
Correct Answer: C
Solution :
\[\underset{\begin{smallmatrix} 1\,vol. \\ 10\,litre \end{smallmatrix}}{\mathop{{{N}_{2}}}}\,+\underset{\begin{smallmatrix} 3\,vol. \\ 30\,litre \end{smallmatrix}}{\mathop{3{{H}_{2}}}}\,\to \underset{\begin{smallmatrix} 2\,vol. \\ 20\,litre \end{smallmatrix}}{\mathop{2N{{H}_{3}}}}\,\] It is given that only 50% of the expected product is formed hence only 10 litre of \[N{{H}_{3}}\]is formed \[{{\text{N}}_{\text{2}}}\,\text{used = 5}\,\text{litres,}\,\text{left = 30-5 = 25}\,\text{litres}\] \[{{\text{H}}_{\text{2}}}\,\text{used = 15}\,\text{litres,}\,\text{left }\,\text{= 30-15 = 15}\,\text{litres}\]
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