A) Acidic nature:\[N{{H}_{3}}<P{{H}_{3}}>As{{H}_{3}}\]
B) \[I{{E}_{1}}:Li<Be<B<C\]
C) Basic nature:\[A{{l}_{2}}{{O}_{3}}<MgO<N{{a}_{2}}O<{{K}_{2}}O\]
D) Ionic radius:\[L{{i}^{+}}<N{{a}^{+}}<{{K}^{+}}<C{{s}^{+}}\]
Correct Answer: B
Solution :
The correct IE order is Li < Be < C. (Be is more than B due to stable \[n{{s}^{2}}\]electronic configuration).
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