A) 3-bromopentane
B) 2-hydroxy propanoic acid
C) 2-butanol
D) 2, 3-dibromopentane
Correct Answer: A
Solution :
a.\[C{{H}_{3}}-C{{H}_{2}}\overset{Br}{\mathop{\overset{|}{\mathop{CH}}\,}}\,CH-C{{H}_{2}}-C{{H}_{3}}\]is not chiral, because of 2 similar groups. b.\[C{{H}_{3}}-\underset{OH}{\overset{H}{\mathop{\underset{{{|}^{*}}}{\overset{|}{\mathop{C}}}\,}}}\,-COOH\] c. \[C{{H}_{3}}-\underset{OH}{\overset{H}{\mathop{\,\underset{|}{\overset{|}{\mathop{{{C}^{*}}}}}\,}}}\,-C{{H}_{2}}-C{{H}_{3}}\] d. \[C{{H}_{3}}-\underset{Br}{\mathop{\underset{|}{\overset{*}{\mathop{C}}}\,}}\,-\underset{Br}{\mathop{\underset{|}{\overset{*}{\mathop{C}}}\,}}\,{{H}_{2}}-C{{H}_{3}}\] Mark * is chiral carbon.
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