A) \[x\]
B) \[\frac{383}{283}x\]
C) \[\frac{10}{110}x\]
D) \[\frac{283}{383}x\]
Correct Answer: D
Solution :
Writing idea 1 gas law, \[PV=nRT\] or \[PV=\frac{m}{M}RT\]or \[\frac{PV}{m}=\frac{1}{M}RT\] or \[\frac{p}{\rho }=\frac{RT}{M}\]or \[\frac{\rho }{P}=\frac{1}{T}\] \[\therefore \] \[\frac{{{\rho }_{1}}/{{P}_{1}}}{{{\rho }_{2}}/{{P}_{2}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\] \[\Rightarrow \] \[\frac{x}{({{\rho }_{2}}/{{\rho }_{2}})}=\frac{383}{283}\]or \[\frac{{{\rho }_{2}}}{{{P}_{2}}}=\frac{283}{283}x\]
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