A) \[\sqrt{\frac{h}{2\pi }}\]
B) \[\frac{l}{m}\sqrt{\frac{h}{\pi }}\]
C) \[\sqrt{\frac{h}{\pi }}\]
D) \[\frac{1}{2m}\sqrt{\frac{h}{\pi }}\]
Correct Answer: D
Solution :
\[\Delta x-\Delta p\]\[\therefore \]\[\Delta x.\Delta p=\frac{h}{4\pi }\] or \[\Delta x=\sqrt{\frac{h}{4\pi }}\] Now, \[\Delta x.\Delta u=\frac{h}{4\pi m}\] \[\therefore \] \[\Delta u=\frac{h}{4\pi m}\times \sqrt{\frac{4\pi }{h}}=\frac{1}{2m}\times \sqrt{\frac{h}{\pi }}\]
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