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NEET Sample Paper NEET Sample Test Paper-37

  • question_answer
    \[{{\,}_{92}}{{U}^{238}}\]nucleus absorbs a neutron and disintegrates into \[{{\,}_{54}}{{X}^{139}},{{\,}_{38}}S{{r}^{94}}\]and X. So what will be the product X?

    A)  3-neutrons   

    B)  2-neutrons

    C)  or-particle    

    D) \[\beta -\]particle

    Correct Answer: A

    Solution :

    \[{{\,}_{92}}{{U}^{235}}+{{\,}_{0}}{{n}^{1}}\to {{\,}_{54}}X{{e}^{139}}+{{\,}_{38}}S{{r}^{94}}+X\] \[92+0=54+38+a\Rightarrow a=0\]\[235+1=139+94+b\Rightarrow b=3\] So, \[X=3\,{{\,}_{0}}{{n}^{1}}\] That is, 3 neutrons.


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