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NEET Sample Paper NEET Sample Test Paper-37

  • question_answer
    0.45 g of an acid (mol wt. = 90) required 20 ml of 0.5 N KOH for complete neutralization. Basicity of acid is

    A)  1              

    B)  2

    C)  3              

    D)  4

    Correct Answer: B

    Solution :

     Normality \[=N=\frac{{{W}_{B}}\times 1000}{Eq.wt\times V}\] \[\therefore \]Eq. Wt \[=\frac{0.45\times 1000}{0.5\times 20}=45\] \[\therefore \]Basicity \[=\frac{Mol.Wt}{Eq.Wt}=\frac{90}{45}=2\]


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