A) \[{{273.16}^{o}}F\]
B) \[273.16\,K\]
C) \[273.16{{\,}^{o}}C\]
D) \[273.16\,R\]
Correct Answer: B
Solution :
Triple point of water is 273.16 K. \[\frac{{{P}_{1}}}{{{P}_{2}}}{{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}=\left( \frac{273-73}{273+327} \right)={{\left( \frac{200}{600} \right)}^{4}}=\frac{1}{81}\]
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