NEET Sample Paper NEET Sample Test Paper-39

  • question_answer
    A mass m is suspended separately by two different springs of spring constant \[{{K}_{1}}\]and\[{{K}_{2}}\]gives the time period\[{{t}_{1}}\]and\[{{t}_{2}}\]respectively. If the  same mass w is connected by both springs as shown in the figure, then time period t is given by the relation                 

    A) \[t={{t}_{1}}+{{t}_{2}}\]

    B)  \[t=\frac{{{t}_{1}}{{t}_{2}}}{{{t}_{1}}+{{t}_{2}}}\]

    C) \[{{t}^{2}}=t_{1}^{2}+t_{2}^{2}\]

    D) \[{{t}^{-2}}=t_{1}^{-2}+t_{2}^{-2}\]  

    Correct Answer: D

    Solution :

     \[{{t}_{1}}=2\pi \sqrt{\frac{m}{{{K}_{1}}}}\]and \[{{t}_{2}}=2\pi \sqrt{\frac{m}{{{K}_{2}}}}\] Equivalent spring constant for shown combination is \[{{K}_{1}}+{{K}_{2}}.\]So time period t is given by \[t=2\pi \sqrt{\frac{m}{{{K}_{1}}+{{K}_{2}}}}\] By solving these equations we get \[{{t}^{-2}}={{t}_{1}}^{-2}+{{t}_{2}}^{-2}\]


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