A) \[\frac{\pi a\sqrt{3}}{2T}\]
B) \[\frac{\pi a}{T}\]
C) \[\frac{3{{\pi }^{2}}a}{T}\]
D) \[\frac{\pi a\sqrt{3}}{T}\]
Correct Answer: D
Solution :
\[v=\frac{dy}{dt}=A\omega \cos \omega t=A\omega \sqrt{1-{{\sin }^{2}}\omega t}\] Here, \[y=\frac{a}{2}\] \[\therefore \] \[v=\omega \sqrt{{{a}^{2}}-\frac{{{a}^{2}}}{4}}=\omega \sqrt{\frac{3{{a}^{2}}}{4}}=\frac{2\pi }{T}\frac{a\sqrt{3}}{2}=\frac{\pi a\sqrt{3}}{T}\]
You need to login to perform this action.
You will be redirected in
3 sec
