NEET Sample Paper NEET Sample Test Paper-3

  • question_answer
    Four bodies of masses 2, 3, 5, and 8 kg are placed at the four corners of a square of side 2 m. The position of CM will be

    A)  \[\left( \frac{8}{9},\frac{13}{9} \right)\]         

    B)  \[\left( \frac{7}{9},\frac{11}{9} \right)\]

    C)  \[\left( \frac{11}{9},\frac{13}{9} \right)\]                             

    D)  \[\left( \frac{11}{9},\frac{8}{9} \right)\]

    Correct Answer: A

    Solution :

        Co-ordinates of the corners of the square are \[(0,0),\] \[(2,0),\]  \[(2,2),\]\[(0,2)\]. \[\therefore \] \[{{x}_{CM}}=\frac{{{m}_{1}}{{x}_{1}}+{{m}_{2}}{{x}_{2}}+{{m}_{3}}{{x}_{3}}+{{m}_{4}}{{x}_{4}}}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}+{{m}_{4}}}\]                          \[=\frac{2\times 0+3\times 2+5\times 2+8\times 0}{2+3+5+8}=\frac{8}{9}\,\,m\] \[{{y}_{CM}}=\frac{{{m}_{1}}{{y}_{1}}+{{m}_{2}}{{y}_{2}}+{{m}_{3}}{{y}_{3}}+{{m}_{4}}{{y}_{4}}}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}+{{m}_{4}}}\]         \[=\frac{2\times 0+3\times 0+5\times 2+8\times 2}{2+3+5+8}=\frac{13}{9}\,m\] Hence co-ordinates of the centre of mass are \[\left( \frac{8}{9},\frac{13}{9} \right)\]            


You need to login to perform this action.
You will be redirected in 3 sec spinner