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NEET Sample Paper NEET Sample Test Paper-3

  • question_answer
    Two simple harmonic motions are represented by the following equations \[{{Y}_{1}}-40\,\sin \omega \] and \[{{Y}_{2}}-100\,(\sin \omega t+c\,\cos \omega )\]. If their diplacement amplitudes are equal then the value of \[cl\] in appropriate units) is:

    A)  \[\sqrt{13}\]               

    B)  \[\sqrt{15}\]

    C)  \[\sqrt{17}\]               

    D)  4

    Correct Answer: B

    Solution :

        As for SHM, first, \[{{A}_{1}}=40\] units And for the second SHM             \[{{A}_{2}}=\sqrt{100+100\,{{C}^{2}}}\]                 \[=10\sqrt{1+{{C}^{2}}}\] As per question, \[{{A}_{1}}={{A}_{2}}\] \[\Rightarrow \]               \[40=10\sqrt{1+{{C}^{2}}}\]                 \[C=\sqrt{15}\]


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