A) \[\tan \theta =\frac{Qq}{2{{\varepsilon }_{0}}mg}\]
B) \[\tan \theta =\frac{Qq}{{{\varepsilon }_{0}}mg}\]
C) \[\cot \theta =\frac{Qq}{2{{\varepsilon }_{0}}mg}\]
D) \[\cot \theta =\frac{Qq}{{{\varepsilon }_{0}}mg}\]
Correct Answer: A
Solution :
From the diagram \[\tan \theta =\frac{Fe}{mg}=\frac{qE}{mg}\] As electric at near point due to a infinitely long thin sheet of charge is \[\frac{\sigma }{2{{\varepsilon }_{0}}}\] \[\Rightarrow \] \[\tan \theta =\frac{qQ/2{{\varepsilon }_{0}}}{mg}=\frac{Qq}{2{{\varepsilon }_{0}}mg}\]You need to login to perform this action.
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