A) 4
B) \[1/4\]
C) \[3/4\]
D) \[4/3\]
Correct Answer: A
Solution :
As relatvie density = Specific gravity and \[RD=\frac{\text{weight of body in air }}{(\text{weight of the body in air}-\text{weight of the body in water)}}\] \[=\frac{{{w}_{a}}}{{{w}_{a}}-{{w}_{w}}}-\frac{{{w}_{a}}}{\Delta w}=\frac{{{w}_{a}}}{{{w}_{a}}/4}\] (Since weight of the body decreases by 25% of its original weight, \[{{w}_{a}}\] (weight in air) \[\Rightarrow \] \[RD=4\]You need to login to perform this action.
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