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NEET Sample Paper NEET Sample Test Paper-3

  • question_answer
    The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun?

    A)  2                    

    B)  3

    C)  4                    

    D)  5

    Correct Answer: C

    Solution :

        According to Kepler's third law of planetary motion, \[{{T}^{2}}\propto {{R}^{3}}\]             \[\therefore \]     \[\left( \frac{{{T}_{A}}}{{{T}_{B}}} \right)={{\left( \frac{{{R}_{A}}}{{{R}_{B}}} \right)}^{3}}\]                 \[\Rightarrow \]               \[{{(8)}^{2}}={{\left( \frac{{{R}_{A}}}{{{R}_{B}}} \right)}^{3}}\]                 \[\Rightarrow \]               \[\frac{{{R}_{A}}}{{{R}_{B}}}=4\]                 \[\Rightarrow \]               \[{{R}_{A}}=4{{R}_{B}}.\]


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