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NEET Sample Paper NEET Sample Test Paper-3

  • question_answer
    There is a current of \[1.344\text{ }A\] in a copper wire whose area of cross-section normal to the length the wire is \[1m{{m}^{2}}\]. If the number of free electrons per \[c{{m}^{3}}\]is \[8.4\times {{10}^{22}},\] then the drift velocity of elections will be:

    A)  \[1.0\,mm/s\]              

    B)  \[10m/s\]

    C)  \[0.1\,mm/s\]       

    D)  \[0.01\,mm/s\]

    Correct Answer: C

    Solution :

        As        \[l=neAVd\] \[\Rightarrow \]    \[1.344=8.4\times {{10}^{22}}\times {{10}^{6}}\times 1.6\times {{10}^{-19}}\]\[\times 1\times {{10}^{-6}}\times Vd\] \[\therefore \]  \[Vd=0.1\,mm/s\]       


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