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NEET Sample Paper NEET Sample Test Paper-3

  • question_answer
    If the energy difference between the ground state of an atom and its excited state is \[4.4\times {{10}^{-14}}J,\] the wavelength of photon required to produce the transition is

    A)  \[2.26\times {{10}^{-12}}m\]     

    B)  \[1.13\times {{10}^{-12}}m\]

    C)  \[8.52\times {{10}^{-16}}m\]

    D)  \[4.52\times {{10}^{-12}}m\]

    Correct Answer: D

    Solution :

        \[\Delta E=hv=\frac{hc}{\lambda }\] \[\lambda =\frac{hc}{\Delta E}=\frac{6.62\times {{10}^{-34}}\times 3\times {{10}^{8}}}{4.4\times {{10}^{-14}}}\] \[=4.52\times {{10}^{-12}}\,m\]


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