NEET Sample Paper NEET Sample Test Paper-40

  • question_answer
    A thin semicircular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in the figure. The potential difference developed across the ring when its speed is v is

    A)  Zero

    B)  \[Bv\pi {{r}^{2}}/2\]and P is at higher potential

    C)  \[\pi rBv\]and R is at higher potential

    D)  2rBv and R is at higher potential

    Correct Answer: D

    Solution :

     The semicircular conducting ring (PQR) can be replaced with a straight rod of length 2r. Hence motional emf induced across the rod


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